What is the derivative of y=-2/(x^3) ?

The derivative of y=-2/(x^3) is 6/(x^4)

What is the first derivative of y=-2/(x^3) ?

The first derivative of y=-2/(x^3) is 6/(x^4)

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derivative of

y = - \frac{2}{x ^{3}}

\frac{6}{x ^{4}}

Solution steps

\frac{d}{d x} (- \frac{2}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 2 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 (- 3 x^{- 3 - 1})

Simplify

- 2 (- 3 x^{- 3 - 1}) : \frac{6}{x ^{4}}

= \frac{6}{x ^{4}}

f (x) = x^{2}, at (- \frac{3}{8})

f (x) = \frac{x ^{2}}{x - 9}

\int_{0}^{2} x + 2 d x

x \to 0 lim (\frac{x}{( x + 0 )})

(4 x^{3} + 5 x^{2})^{5}

What is the derivative of y=-2/(x^3) ?
The derivative of y=-2/(x^3) is 6/(x^4)
What is the first derivative of y=-2/(x^3) ?
The first derivative of y=-2/(x^3) is 6/(x^4)