What is the solution for x(dy)/(dx)+2y= 1/(x^3) ?

The solution for x(dy)/(dx)+2y= 1/(x^3) is y=-1/(x^3)+(c_{1})/(x^2)

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x(dy)/(dx)+2y= 1/(x^3)

x \frac{d y}{d x} + 2 y = \frac{1}{x ^{3}}

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

Solution steps

x \frac{d y}{d x} + 2 y = \frac{1}{x ^{3}}

Solve linear ODE:

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

x^{2} + 7 x - 5

\int (\frac{3}{x} - \frac{x x}{4}) d x

z^{^{'}}

\frac{d}{d x} (y^{2} + x^{2})

x^{2} (\frac{d y}{d x}) = y - x y

What is the solution for x(dy)/(dx)+2y= 1/(x^3) ?
The solution for x(dy)/(dx)+2y= 1/(x^3) is y=-1/(x^3)+(c_{1})/(x^2)