What is the derivative of (e^x/(8x^2+1)) ?

The derivative of (e^x/(8x^2+1)) is (e^x(8x^2+1)-16xe^x)/((8x^2+1)^2)

What is the first derivative of (e^x/(8x^2+1)) ?

The first derivative of (e^x/(8x^2+1)) is (e^x(8x^2+1)-16xe^x)/((8x^2+1)^2)

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\frac{d}{d x} (\frac{e ^{x}}{8 x ^{2} + 1})

\frac{e ^{x} ( 8 x ^{2} + 1 ) - 16 x e ^{x}}{( 8 x ^{2} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{8 x ^{2} + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} ) ( 8 x ^{2} + 1 ) - \frac{d}{d x} ( 8 x ^{2} + 1 ) e ^{x}}{( 8 x ^{2} + 1 ) ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (8 x^{2} + 1) = 16 x

= \frac{e ^{x} ( 8 x ^{2} + 1 ) - 16 x e ^{x}}{( 8 x ^{2} + 1 ) ^{2}}

csc (y) d x + sec (x) d y = 0

f (x) = e^{2 x} arcsin (x)

\frac{d}{d x} (10 - x^{2})

y = x^{3} - 9 x

\int x^{2} 5 + x d x

What is the derivative of (e^x/(8x^2+1)) ?
The derivative of (e^x/(8x^2+1)) is (e^x(8x^2+1)-16xe^x)/((8x^2+1)^2)
What is the first derivative of (e^x/(8x^2+1)) ?
The first derivative of (e^x/(8x^2+1)) is (e^x(8x^2+1)-16xe^x)/((8x^2+1)^2)