What is the derivative of 3x^2y ?

The derivative of 3x^2y is 3(2xy+(dy)/(dx)x^2)

What is the first derivative of 3x^2y ?

The first derivative of 3x^2y is 3(2xy+(dy)/(dx)x^2)

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\frac{d}{d x} (3 x^{2} y)

3 (2 x y + \frac{d y}{d x} x^{2})

Solution steps

\frac{d}{d x} (3 x^{2} y)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{2} y)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = y

= 3 (\frac{d}{d x} (x^{2}) y + \frac{d y}{d x} x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= 3 (2 x y + \frac{d y}{d x} x^{2})

x \to 2 lim (x^{3} + 2 x^{2} - x - 4)

\frac{d}{d x} ((3 x^{2} + 5) (3 x - 1)^{2})

2 x^{2} e^{x}

f (x) = \frac{3}{4 x ^{5}}

\frac{d}{d x} (4 x^{8} + 3 e^{7 x})

What is the derivative of 3x^2y ?
The derivative of 3x^2y is 3(2xy+(dy)/(dx)x^2)
What is the first derivative of 3x^2y ?
The first derivative of 3x^2y is 3(2xy+(dy)/(dx)x^2)