What is (\partial)/(\partial x)(c(1+m*x)-c(1+m)^x) ?

The answer to (\partial)/(\partial x)(c(1+m*x)-c(1+m)^x) is cm-c(1+m)^xln(1+m)

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(\partial)/(\partial x)(c(1+m*x)-c(1+m)^x)

\frac{\partial}{\partial x} (c (1 + m \cdot x) - c (1 + m)^{x})

c m - c (1 + m)^{x} ln (1 + m)

Solution steps

\frac{\partial}{\partial x} (c (1 + m x) - c (1 + m)^{x})

Treat

c, m

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (c (1 + m x)) - \frac{\partial}{\partial x} (c (1 + m)^{x})

\frac{\partial}{\partial x} (c (1 + m x)) = c m

\frac{\partial}{\partial x} (c (1 + m)^{x}) = c (1 + m)^{x} ln (1 + m)

= c m - c (1 + m)^{x} ln (1 + m)

n = 1 \sum \infty \frac{n}{3 n ^{3} + 1}

\frac{d}{d x} (\frac{x}{2})

y^{^{''}} - y^{^{'}} + \frac{1}{4} y = 0

x \to - 1 + lim (\frac{3 x - 5}{x + 1})

- \frac{3}{x}

What is (\partial)/(\partial x)(c(1+m*x)-c(1+m)^x) ?
The answer to (\partial)/(\partial x)(c(1+m*x)-c(1+m)^x) is cm-c(1+m)^xln(1+m)