What is the derivative of 6/((x-3^4)) ?

The derivative of 6/((x-3^4)) is -(24)/((x-3)^5)

What is the first derivative of 6/((x-3^4)) ?

The first derivative of 6/((x-3^4)) is -(24)/((x-3)^5)

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\frac{d}{d x} (\frac{6}{( x - 3 ) ^{4}})

- \frac{24}{( x - 3 ) ^{5}}

Solution steps

\frac{d}{d x} (\frac{6}{( x - 3 ) ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{1}{( x - 3 ) ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 6 \frac{d}{d x} ((x - 3)^{- 4})

Apply the chain rule:

- \frac{4}{( x - 3 ) ^{5}} \frac{d}{d x} (x - 3)

= - \frac{4}{( x - 3 ) ^{5}} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= 6 (- \frac{4}{( x - 3 ) ^{5}} \cdot 1)

Simplify

6 (- \frac{4}{( x - 3 ) ^{5}} \cdot 1) : - \frac{24}{( x - 3 ) ^{5}}

= - \frac{24}{( x - 3 ) ^{5}}

\int 7 x \cdot \frac{e ^{3 x}}{7} d x

x \to 0 + lim (x + 2)

3 - sin (2 t) + e^{5 t}

38 (2 e^{x^{2}} x^{2} + e^{x^{2}})

\frac{d y}{d x} = sin (x^{2})

What is the derivative of 6/((x-3^4)) ?
The derivative of 6/((x-3^4)) is -(24)/((x-3)^5)
What is the first derivative of 6/((x-3^4)) ?
The first derivative of 6/((x-3^4)) is -(24)/((x-3)^5)