What is the solution for (dy)/(dx)=sin(x^2) ?

The solution for (dy)/(dx)=sin(x^2) is y=sqrt(pi/2)\S(sqrt(2/pi)x)+c_{1}

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(dy)/(dx)=sin(x^2)

\frac{d y}{d x} = sin (x^{2})

y = \frac{π}{2} § (\frac{2}{π} x) + c_{1}

Solution steps

\frac{d y}{d x} = sin (x^{2})

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = sin (x^{2})

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int sin (x^{2}) d x

\int sin (x^{2}) d x = \frac{π}{2} § (\frac{2}{π} x) + c_{1}

y = \frac{π}{2} § (\frac{2}{π} x) + c_{1}

\frac{d}{d x} ((2 + 1) e^{2 x})

\int \frac{e ^{x - 1 + l n (x - 1)}}{e ^{2 x}} d x

\int (\frac{15}{x ^{2} + 1}) d x

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\int_{0}^{1} \frac{13}{x ^{5}} d x

What is the solution for (dy)/(dx)=sin(x^2) ?
The solution for (dy)/(dx)=sin(x^2) is y=sqrt(pi/2)\S(sqrt(2/pi)x)+c_{1}