What is the integral from 0 to 1 of (13)/(x^5) ?

The integral from 0 to 1 of (13)/(x^5) is diverges

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integral from 0 to 1 of (13)/(x^5)

\int_{0}^{1} \frac{13}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{13}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 13 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 13 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

2 x^{2}

f (x) = \frac{3}{5} x^{10}

\frac{d}{d x} \frac{( x ^{2} - 4 ) ^{3}}{6}

\int \frac{1}{y ( y + 1 )} d y

y^{^{'}} = 2 t y (1 - y)

What is the integral from 0 to 1 of (13)/(x^5) ?
The integral from 0 to 1 of (13)/(x^5) is diverges