What is the derivative of 4e^x+x ?

The derivative of 4e^x+x is 4e^x+1

What is the first derivative of 4e^x+x ?

The first derivative of 4e^x+x is 4e^x+1

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derivative of

4 e^{x} + x

4 e^{x} + 1

Solution steps

\frac{d}{d x} (4 e^{x} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 e^{x}) + \frac{d x}{d x}

\frac{d}{d x} (4 e^{x}) = 4 e^{x}

\frac{d x}{d x} = 1

= 4 e^{x} + 1

\frac{d y}{d x} = - \frac{2 x}{y}

(x + 1) (4 x^{2} - 4 x - 8)

\frac{\partial}{\partial x} (x^{3} y - x y^{3})

(- 12 x y^{2} - 12 y) + (- 12 x^{2} y - 12 x) y^{^{'}} = 0

\int e^{- 4 x} d x

What is the derivative of 4e^x+x ?
The derivative of 4e^x+x is 4e^x+1
What is the first derivative of 4e^x+x ?
The first derivative of 4e^x+x is 4e^x+1