What is the solution for (dy)/(dx)=(yx)/(x-1) ?

The solution for (dy)/(dx)=(yx)/(x-1) is y=e^{x-1+c_{1}}x-e^{x-1+c_{1}}

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(dy)/(dx)=(yx)/(x-1)

\frac{d y}{d x} = \frac{y x}{x - 1}

y = e^{x - 1 + c_{1}} x - e^{x - 1 + c_{1}}

Solution steps

\frac{d y}{d x} = \frac{y x}{x - 1}

Solve separable ODE:

y = e^{x - 1 + c_{1}} x - e^{x - 1 + c_{1}}

y = e^{x - 1 + c_{1}} x - e^{x - 1 + c_{1}}

\int \frac{( cos ( x ) )}{sin ^{2} ( x )} d x

\int 2 sin^{2} (x co) s^{3} x d x

y^{^{'}} + 5 y = 2 x y^{5}

\frac{d y}{d x} + 2 x^{- 1} y = 6 x^{4} y^{2}

(\frac{1}{8}) y^{^{''}} + 4 y^{^{'}} + 20 y = 0

What is the solution for (dy)/(dx)=(yx)/(x-1) ?
The solution for (dy)/(dx)=(yx)/(x-1) is y=e^{x-1+c_{1}}x-e^{x-1+c_{1}}