What is the solution for (dy)/(dx)+2x^{-1}y=6x^4y^2 ?

The solution for (dy)/(dx)+2x^{-1}y=6x^4y^2 is y= 1/(x^2(-2x^3+c_{1))}

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(dy)/(dx)+2x^{-1}y=6x^4y^2

\frac{d y}{d x} + 2 x^{- 1} y = 6 x^{4} y^{2}

y = \frac{1}{x ^{2} ( - 2 x ^{3} + c _{1} )}

Solution steps

\frac{d y}{d x} + 2 x^{- 1} y = 6 x^{4} y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ^{2} ( - 2 x ^{3} + c _{1} )}

y = \frac{1}{x ^{2} ( - 2 x ^{3} + c _{1} )}

(\frac{1}{8}) y^{^{''}} + 4 y^{^{'}} + 20 y = 0

\int 30 (x + 9) (x + 9)^{4} d x

\frac{d}{d x} (\frac{x ^{3}}{2} - \frac{3}{x ^{2}})

y^{^{''}} - 7 y^{^{'}} + 10 y = - 2 cos (2 t)

f (x) = 4 x - 1

What is the solution for (dy)/(dx)+2x^{-1}y=6x^4y^2 ?
The solution for (dy)/(dx)+2x^{-1}y=6x^4y^2 is y= 1/(x^2(-2x^3+c_{1))}