What is the derivative of y=x^{7/5}+e^{-4x} ?

The derivative of y=x^{7/5}+e^{-4x} is (7x^{2/5})/5-4e^{-4x}

What is the first derivative of y=x^{7/5}+e^{-4x} ?

The first derivative of y=x^{7/5}+e^{-4x} is (7x^{2/5})/5-4e^{-4x}

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derivative of

y = x^{\frac{7}{5}} + e^{- 4 x}

\frac{7 x ^{\frac{2}{5}}}{5} - 4 e^{- 4 x}

Solution steps

\frac{d}{d x} (x^{\frac{7}{5}} + e^{- 4 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{\frac{7}{5}}) + \frac{d}{d x} (e^{- 4 x})

\frac{d}{d x} (x^{\frac{7}{5}}) = \frac{7 x ^{\frac{2}{5}}}{5}

\frac{d}{d x} (e^{- 4 x}) = - 4 e^{- 4 x}

= \frac{7 x ^{\frac{2}{5}}}{5} - 4 e^{- 4 x}

\frac{d}{d t} (t + 1)

(- 4.3) (3.1)

\frac{d}{d x} (x (3 x + 1))

\frac{\partial}{\partial x} (arcsec (- x))

What is the derivative of y=x^{7/5}+e^{-4x} ?
The derivative of y=x^{7/5}+e^{-4x} is (7x^{2/5})/5-4e^{-4x}
What is the first derivative of y=x^{7/5}+e^{-4x} ?
The first derivative of y=x^{7/5}+e^{-4x} is (7x^{2/5})/5-4e^{-4x}