What is the integral of sin^4(x)cos(x) ?

The integral of sin^4(x)cos(x) is (sin^5(x))/5+C

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integral of sin^4(x)cos(x)

\int sin^{4} (x) cos (x) d x

\frac{sin ^{5} ( x )}{5} + C

Solution steps

\int sin^{4} (x) cos (x) d x

Apply u-substitution

: \int u^{4} d u

= \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= \frac{u ^{5}}{5}

Substitute back

u = sin (x)

= \frac{sin ^{5} ( x )}{5}

Add a constant to the solution

= \frac{sin ^{5} ( x )}{5} + C

\frac{\partial}{\partial x} (x^{2} + y^{2} - y cos (x))

\int_{1}^{2} \frac{1}{8 ( 2 + 2 x - x ^{2} )} d x

\int - \frac{x ^{2}}{( - x + 1 ) ( x + 1 )} d x

\frac{d}{d x} (A e^{x} + B e^{- x})

x y^{^{'}} = ((1 - x) y + x^{2} + x^{3}), y (3) = 2

What is the integral of sin^4(x)cos(x) ?
The integral of sin^4(x)cos(x) is (sin^5(x))/5+C