What is the derivative of x^5-2x^3+x-1 ?

The derivative of x^5-2x^3+x-1 is 5x^4-6x^2+1

What is the first derivative of x^5-2x^3+x-1 ?

The first derivative of x^5-2x^3+x-1 is 5x^4-6x^2+1

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\frac{d}{d x} (x^{5} - 2 x^{3} + x - 1)

5 x^{4} - 6 x^{2} + 1

Solution steps

\frac{d}{d x} (x^{5} - 2 x^{3} + x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{5}) - \frac{d}{d x} (2 x^{3}) + \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 5 x^{4} - 6 x^{2} + 1 - 0

Simplify

= 5 x^{4} - 6 x^{2} + 1

y = - 11 x + 3, y = - x, [0, 0.3]

\frac{3}{4 x}

\int sin^{2} (3 θ) d θ

\int - \frac{3}{x} + 3 e^{x} d x

\int (\frac{sin ( x )}{2 e ^{x}}) d x

What is the derivative of x^5-2x^3+x-1 ?
The derivative of x^5-2x^3+x-1 is 5x^4-6x^2+1
What is the first derivative of x^5-2x^3+x-1 ?
The first derivative of x^5-2x^3+x-1 is 5x^4-6x^2+1