What is the derivative of sqrt(1+9x) ?

The derivative of sqrt(1+9x) is 9/(2sqrt(1+9x))

What is the first derivative of sqrt(1+9x) ?

The first derivative of sqrt(1+9x) is 9/(2sqrt(1+9x))

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\frac{d}{d x} (1 + 9 x)

\frac{9}{2 1 + 9 x}

Solution steps

\frac{d}{d x} (1 + 9 x)

Apply the chain rule:

\frac{1}{2 1 + 9 x} \frac{d}{d x} (1 + 9 x)

= \frac{1}{2 1 + 9 x} \frac{d}{d x} (1 + 9 x)

\frac{d}{d x} (1 + 9 x) = 9

= \frac{1}{2 1 + 9 x} \cdot 9

Simplify

\frac{1}{2 1 + 9 x} \cdot 9 : \frac{9}{2 1 + 9 x}

= \frac{9}{2 1 + 9 x}

a^{8} + cos^{8} (x)

\int \frac{3 x ^{5} - 2 x ^{3} + 5 x ^{2} - 2}{x ^{3} + 1} d x

x \to 4 lim (\frac{3 x}{4} + 2)

\frac{d}{d x} ((x^{2} - 3)^{3})

f (x) = (x - 2) (5 x + 3)

What is the derivative of sqrt(1+9x) ?
The derivative of sqrt(1+9x) is 9/(2sqrt(1+9x))
What is the first derivative of sqrt(1+9x) ?
The first derivative of sqrt(1+9x) is 9/(2sqrt(1+9x))