What is the integral of e^{-15x} ?

The integral of e^{-15x} is -1/15 e^{-15x}+C

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integral of e^{-15x}

\int e^{- 15 x} d x

- \frac{1}{15} e^{- 15 x} + C

Solution steps

\int e^{- 15 x} d x

Apply u-substitution

: \int - \frac{1}{15} e^{u} d u

= \int - \frac{1}{15} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{15} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - \frac{1}{15} e^{u}

Substitute back

u = - 15 x

= - \frac{1}{15} e^{- 15 x}

Add a constant to the solution

= - \frac{1}{15} e^{- 15 x} + C

\frac{1}{s ^{2} + 7}

\int (n + 3)^{3} d n

\int ln^{2} (x - 9) d x

ln (x^{2}) - \frac{1}{x ^{2}} - 5

y^{3} = 126 - x^{3}, at x = 5