What is the limit as x approaches 0 of sin((2pi)/x) ?

The limit as x approaches 0 of sin((2pi)/x) is diverges

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limit as x approaches 0 of sin((2pi)/x)

x \to 0 lim (sin (\frac{2 π}{x}))

diverges

Solution steps

x \to 0 lim (sin (\frac{2 π}{x}))

Apply Limit Divergence Criterion:

diverges

= diverges

\int \frac{6 + x}{6 - x} d x

\frac{\partial}{\partial x} (\frac{x ^{2} - y ^{2}}{x ^{2} + y ^{2}})

\int x^{4 n} d x

f (x) = \frac{2 x - 1}{x + 1}, at x = 1

3 x - cos (x)

What is the limit as x approaches 0 of sin((2pi)/x) ?
The limit as x approaches 0 of sin((2pi)/x) is diverges