What is the tangent of f(x)=(2x-1)/(x+1),\at x=1 ?

The tangent of f(x)=(2x-1)/(x+1),\at x=1 is y= 3/4 x-1/4

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tangent of f(x)=(2x-1)/(x+1),\at x=1

tangent of

f (x) = \frac{2 x - 1}{x + 1}, at x = 1

y = \frac{3}{4} x - \frac{1}{4}

Solution steps

Find the tangent point:

(1, \frac{1}{2})

Find the slope of

f (x) = \frac{2 x - 1}{x + 1} : \frac{df ( x )}{d x} = \frac{3}{( x + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{2 x - 1}{x + 1}

x = 1 : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(1, \frac{1}{2}) : y = \frac{3}{4} x - \frac{1}{4}

y = \frac{3}{4} x - \frac{1}{4}

3 x - cos (x)

\frac{d}{d x} (\frac{6 x + x ^{2}}{( 3 + x ) ^{2}})

n \to \infty lim (0. 5^{n})

6 x e^{x}

\frac{( 3 s + 2 )}{( s ^{2} + 4 s + 20 )}

What is the tangent of f(x)=(2x-1)/(x+1),\at x=1 ?
The tangent of f(x)=(2x-1)/(x+1),\at x=1 is y= 3/4 x-1/4