What is the limit as n approaches infinity of 0.5^n ?

The limit as n approaches infinity of 0.5^n is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as n approaches infinity of 0.5^n

n \to \infty lim (0. 5^{n})

0

Solution steps

n \to \infty lim (0. 5^{n})

Apply the common limit:

x \to \infty lim (a^{x}) = 0, 0 < a < 1

= 0

6 x e^{x}

\frac{( 3 s + 2 )}{( s ^{2} + 4 s + 20 )}

x \to 0 + lim (\frac{x}{1 + ln ( x )})

y^{^{''}} + 7 y^{^{'}} = 0, y (0) = 1, y^{^{'}} (0) = 1

\frac{d y}{d x} = 2 y x + y x^{2}, y (- 3) = 1

What is the limit as n approaches infinity of 0.5^n ?
The limit as n approaches infinity of 0.5^n is 0