What is the limit as x approaches 0 of 4/(x(x+2)) ?

The limit as x approaches 0 of 4/(x(x+2)) is diverges

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limit as x approaches 0 of 4/(x(x+2))

x \to 0 lim (\frac{4}{x ( x + 2 )})

diverges

Solution steps

x \to 0 lim (\frac{4}{x ( x + 2 )})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{4}{x ( x + 2 )}) = \infty

x \to 0 - lim (\frac{4}{x ( x + 2 )}) = - \infty

= diverges

(5 x - 3)^{4} (2 x - 7)^{- 3}

x \to 0 + lim (\frac{8}{x} - \frac{8}{∣ x ∣})

\frac{d}{d x} (\frac{3 x ^{2}}{x})

\frac{d}{d x} (- 0.4 x^{3})

x \to 0 lim (\frac{5}{4} π - π)

What is the limit as x approaches 0 of 4/(x(x+2)) ?
The limit as x approaches 0 of 4/(x(x+2)) is diverges