What is the tangent of y=2sqrt(x),(1,2) ?

The tangent of y=2sqrt(x),(1,2) is y=x+1

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tangent of y=2sqrt(x),(1,2)

tangent of

y = 2 x, (1, 2)

y = x + 1

Solution steps

Find the slope of

y = 2 x : \frac{d y}{d x} = \frac{1}{x}

Compute the slope of

y = 2 x

(1, 2) : m = 1

Find the line with slope m=

1

and passing through

(1, 2) : y = x + 1

y = x + 1

y = \frac{x ^{4}}{16}

\int x (3 x - 5)^{10} d x

\int \frac{1}{( x ) ln ( x )} d x

\int \frac{8}{1 + 9 r ^{2}} d r

\frac{d}{d x} (\frac{( x ^{2} )}{x ^{2} + 4})

What is the tangent of y=2sqrt(x),(1,2) ?
The tangent of y=2sqrt(x),(1,2) is y=x+1