What is the d/(dy)(sqrt(36-y^2)) ?

The d/(dy)(sqrt(36-y^2)) is -y/(sqrt(36-y^2))

What is the first d/(dy)(sqrt(36-y^2)) ?

The first d/(dy)(sqrt(36-y^2)) is -y/(sqrt(36-y^2))

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\frac{d}{d y} (36 - y^{2})

- \frac{y}{36 - y ^{2}}

Solution steps

\frac{d}{d y} (36 - y^{2})

Apply the chain rule:

\frac{1}{2 36 - y ^{2}} \frac{d}{d y} (36 - y^{2})

= \frac{1}{2 36 - y ^{2}} \frac{d}{d y} (36 - y^{2})

\frac{d}{d y} (36 - y^{2}) = - 2 y

= \frac{1}{2 36 - y ^{2}} (- 2 y)

Simplify

\frac{1}{2 36 - y ^{2}} (- 2 y) : - \frac{y}{36 - y ^{2}}

= - \frac{y}{36 - y ^{2}}

\frac{\partial}{\partial x} (7 y e^{8 x})

x \to 0 lim (\frac{3}{e ^{x} - 1} - \frac{1}{3})

\int - 4 cos (2 t + π) d t

\int \frac{4400 x}{4 x ^{2} + 320} d x

\frac{\partial}{\partial x} (8 y^{9} x^{7} - 7 y^{8} x^{6})

What is the d/(dy)(sqrt(36-y^2)) ?
The d/(dy)(sqrt(36-y^2)) is -y/(sqrt(36-y^2))
What is the first d/(dy)(sqrt(36-y^2)) ?
The first d/(dy)(sqrt(36-y^2)) is -y/(sqrt(36-y^2))