What is the integral of (x^3-27)/(x-3) ?

The integral of (x^3-27)/(x-3) is (x^3)/3+(3x^2)/2+9x+C

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integral of (x^3-27)/(x-3)

\int \frac{x ^{3} - 27}{x - 3} d x

\frac{x ^{3}}{3} + \frac{3 x ^{2}}{2} + 9 x + C

Solution steps

\int \frac{x ^{3} - 27}{x - 3} d x

Long division

\frac{x ^{3} - 27}{x - 3} : x^{2} + 3 x + 9

= \int x^{2} + 3 x + 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int 3 x d x + \int 9 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 9 d x = 9 x

= \frac{x ^{3}}{3} + \frac{3 x ^{2}}{2} + 9 x

Add a constant to the solution

= \frac{x ^{3}}{3} + \frac{3 x ^{2}}{2} + 9 x + C

\int_{2}^{5} 6 x d x

y^{^{'}} + 2 y = e^{- 2 t}

x \to 0 lim ((e^{x} + x)^{\frac{2}{x}})

\frac{d}{d t} (1 - t^{2})

What is the integral of (x^3-27)/(x-3) ?
The integral of (x^3-27)/(x-3) is (x^3)/3+(3x^2)/2+9x+C