What is the integral from 2 to 5 of 6sqrt(x) ?

The integral from 2 to 5 of 6sqrt(x) is 2(10sqrt(5)-4sqrt(2))

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integral from 2 to 5 of 6sqrt(x)

\int_{2}^{5} 6 x d x

2 (105 - 42)

Decimal Notation

33.40765 \dots

Solution steps

\int_{2}^{5} 6 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{2}^{5} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{2}^{5}

= 6 [\frac{2}{3} x^{\frac{3}{2}}]_{2}^{5}

Compute the boundaries:

\frac{10 5 - 4 2}{3}

= 6 \cdot \frac{10 5 - 4 2}{3}

Simplify

= 2 (105 - 42)

y^{^{'}} + 2 y = e^{- 2 t}

x \to 0 lim ((e^{x} + x)^{\frac{2}{x}})

\frac{d}{d t} (1 - t^{2})

\frac{\partial}{\partial x} (\frac{4}{x y})

What is the integral from 2 to 5 of 6sqrt(x) ?
The integral from 2 to 5 of 6sqrt(x) is 2(10sqrt(5)-4sqrt(2))