What is (\partial)/(\partial y)(cos(2x-y)) ?

The answer to (\partial)/(\partial y)(cos(2x-y)) is sin(2x-y)

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(\partial)/(\partial y)(cos(2x-y))

\frac{\partial}{\partial y} (cos (2 x - y))

sin (2 x - y)

Solution steps

\frac{\partial}{\partial y} (cos (2 x - y))

Treat

x

as a constant

Apply the chain rule:

- sin (2 x - y) \frac{\partial}{\partial y} (2 x - y)

= - sin (2 x - y) \frac{\partial}{\partial y} (2 x - y)

\frac{\partial}{\partial y} (2 x - y) = - 1

= - sin (2 x - y) (- 1)

Simplify

= sin (2 x - y)

x \to 1 lim (x^{2} - 4 x + 3)

\int \frac{x}{e ^{- x^{2}}} d x

\frac{\partial}{\partial x} (2 x ln (y))

\frac{d}{d x} (2 x^{2} - e^{x})

\frac{d}{d x} (e^{π} - e^{π x} + 2 π^{2})

What is (\partial)/(\partial y)(cos(2x-y)) ?
The answer to (\partial)/(\partial y)(cos(2x-y)) is sin(2x-y)