What is the integral of 10\sqrt[3]{x^2} ?

The integral of 10\sqrt[3]{x^2} is 6x^{5/3}+C

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integral of 10\sqrt[3]{x^2}

6 x^{\frac{5}{3}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= 10 \cdot \int x^{\frac{2}{3}} d x

Apply the Power Rule

: \frac{3}{5} x^{\frac{5}{3}}

= 10 \cdot \frac{3}{5} x^{\frac{5}{3}}

Simplify

10 \cdot \frac{3}{5} x^{\frac{5}{3}} : 6 x^{\frac{5}{3}}

= 6 x^{\frac{5}{3}}

Add a constant to the solution

= 6 x^{\frac{5}{3}} + C

\frac{1}{( 1 - x )}

3 x + 7

\frac{\partial}{\partial x} (- e^{x} sin (y))

\frac{d}{d x} (e^{x} sin (6 x))

y = (- 4) + x^{2}, (1, - 3)

What is the integral of 10\sqrt[3]{x^2} ?
The integral of 10\sqrt[3]{x^2} is 6x^{5/3}+C