What is the derivative of 7/(x^4) ?

The derivative of 7/(x^4) is -(28)/(x^5)

What is the first derivative of 7/(x^4) ?

The first derivative of 7/(x^4) is -(28)/(x^5)

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\frac{d}{d x} (\frac{7}{x ^{4}})

- \frac{28}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{7}{x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 (- 4 x^{- 4 - 1})

Simplify

7 (- 4 x^{- 4 - 1}) : - \frac{28}{x ^{5}}

= - \frac{28}{x ^{5}}

x \to 0 lim (- 2 csc (2 x))

\frac{\partial}{\partial x} (- sin (x))

\frac{d}{d x} (\frac{1 - x}{2 x})

n = 1 \sum \infty (- 1)^{n} \frac{1}{n}

\frac{- u ^{2} + 8}{( u ^{2} + 8 ) ^{2}}

What is the derivative of 7/(x^4) ?
The derivative of 7/(x^4) is -(28)/(x^5)
What is the first derivative of 7/(x^4) ?
The first derivative of 7/(x^4) is -(28)/(x^5)