What is the solution for y^'=(2x^5e^{y/x}+x^3y^2)/(x^4y) ?

The solution for y^'=(2x^5e^{y/x}+x^3y^2)/(x^4y) is y=-\W((2ln(x)+c_{1})/e)x-x

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y^'=(2x^5e^{y/x}+x^3y^2)/(x^4y)

y^{^{'}} = \frac{2 x ^{5} e ^{\frac{y}{x}} + x ^{3} y ^{2}}{x ^{4} y}

y = - W (\frac{2 ln ( x ) + c _{1}}{e}) x - x

Solution steps

y^{'} (x) = \frac{2 x ^{5} e ^{\frac{y}{x}} + x ^{3} y ^{2}}{x ^{4} y}

Solve using substitution:

y = - W (\frac{2 ln ( x ) + c _{1}}{e}) x - x

y = - W (\frac{2 ln ( x ) + c _{1}}{e}) x - x

f (x) = - 2 x^{2} + 4 x - 4, at x = 3

\frac{\partial}{\partial x} (x + 3 y)

(lo g_{e} (x))^{^{'}}

(- 3, 5), (3, 5)

y^{^{'}} = 2 x + 3

What is the solution for y^'=(2x^5e^{y/x}+x^3y^2)/(x^4y) ?
The solution for y^'=(2x^5e^{y/x}+x^3y^2)/(x^4y) is y=-\W((2ln(x)+c_{1})/e)x-x