What is the integral of (7/(x^3)) ?

The integral of (7/(x^3)) is -7/(2x^2)+C

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integral of (7/(x^3))

\int (\frac{7}{x ^{3}}) d x

- \frac{7}{2 x ^{2}} + C

Solution steps

\int \frac{7}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int \frac{1}{x ^{3}} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= 7 (- \frac{1}{2 x ^{2}})

Simplify

7 (- \frac{1}{2 x ^{2}}) : - \frac{7}{2 x ^{2}}

= - \frac{7}{2 x ^{2}}

Add a constant to the solution

= - \frac{7}{2 x ^{2}} + C

\frac{\partial}{\partial x} (x^{3} e^{5 x y})

\frac{\partial}{\partial x} (\frac{( 7 x + 4 )}{4 y + 1})

(e^{4 x})^{2}

y^{^{'}} + 2 y = 50 e^{- 10 t}

\frac{d}{d x} (\frac{- x}{x ^{2} + 1})