What is the integral from 0 to 7 of-30x^2+340x ?

The integral from 0 to 7 of-30x^2+340x is 4900

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integral from 0 to 7 of-30x^2+340x

\int_{0}^{7} - 30 x^{2} + 340 x d x

4900

Solution steps

\int_{0}^{7} - 30 x^{2} + 340 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{7} 30 x^{2} d x + \int_{0}^{7} 340 x d x

\int_{0}^{7} 30 x^{2} d x = 3430

\int_{0}^{7} 340 x d x = 8330

= - 3430 + 8330

Simplify

= 4900

x \to + 0 lim (\frac{1}{x - 1})

(x^{2} - y^{2}) d x + 3 x y d y = 0

\int_{4}^{7} \frac{1}{x - 3} d x

\int - \frac{4}{3} x^{3} 2 x - 1 d x

ln (x^{2} + 1)

What is the integral from 0 to 7 of-30x^2+340x ?
The integral from 0 to 7 of-30x^2+340x is 4900