What is the limit as x approaches 3 of (x^2+1)/(x-3) ?

The limit as x approaches 3 of (x^2+1)/(x-3) is diverges

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limit as x approaches 3 of (x^2+1)/(x-3)

x \to 3 lim (\frac{x ^{2} + 1}{x - 3})

diverges

Solution steps

x \to 3 lim (\frac{x ^{2} + 1}{x - 3})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{x ^{2} + 1}{x - 3}) = \infty

x \to 3 - lim (\frac{x ^{2} + 1}{x - 3}) = - \infty

= diverges

\frac{d}{d x} (sin (x^{2} + 5))

\frac{d}{d x} (\frac{7 x}{e ^{x}})

n = 1 \sum \infty \frac{9}{1 0 ^{n}}

\frac{d}{d t} (cos (3 t))

n = 0 \sum \infty \frac{1}{n \cdot ln ( n )}

What is the limit as x approaches 3 of (x^2+1)/(x-3) ?
The limit as x approaches 3 of (x^2+1)/(x-3) is diverges