What is the derivative of 9x^{7/2} ?

The derivative of 9x^{7/2} is (63x^{5/2})/2

What is the first derivative of 9x^{7/2} ?

The first derivative of 9x^{7/2} is (63x^{5/2})/2

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\frac{d}{d x} (9 x^{\frac{7}{2}})

\frac{63 x ^{\frac{5}{2}}}{2}

Solution steps

\frac{d}{d x} (9 x^{\frac{7}{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (x^{\frac{7}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 \cdot \frac{7}{2} x^{\frac{7}{2} - 1}

Simplify

9 \cdot \frac{7}{2} x^{\frac{7}{2} - 1} : \frac{63 x ^{\frac{5}{2}}}{2}

= \frac{63 x ^{\frac{5}{2}}}{2}

f (x) = \frac{x ^{3} + 2 x ^{2} + x + 2}{x + 2}

\int e^{- 6 x} tan (e^{- 6 x}) d x

y^{^{'}} - (\frac{2 x}{1 + x ^{2}}) y = 0

\frac{\partial}{\partial x} (1 0^{x})

x \to - 3 lim (- f (x))

What is the derivative of 9x^{7/2} ?
The derivative of 9x^{7/2} is (63x^{5/2})/2
What is the first derivative of 9x^{7/2} ?
The first derivative of 9x^{7/2} is (63x^{5/2})/2