What is the derivative of (6x+7^2) ?

The derivative of (6x+7^2) is 12(6x+7)

What is the first derivative of (6x+7^2) ?

The first derivative of (6x+7^2) is 12(6x+7)

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\frac{d}{d x} ((6 x + 7)^{2})

12 (6 x + 7)

Solution steps

\frac{d}{d x} ((6 x + 7)^{2})

Apply the chain rule:

2 (6 x + 7) \frac{d}{d x} (6 x + 7)

= 2 (6 x + 7) \frac{d}{d x} (6 x + 7)

\frac{d}{d x} (6 x + 7) = 6

= 2 (6 x + 7) \cdot 6

Simplify

= 12 (6 x + 7)

\int x^{2} \cdot ln^{2} (x) d x

f (x) = (\frac{1}{x} - \frac{1}{a})^{2}

\frac{7}{x}

\frac{d}{d x} (cosh (cos (x)))

x \to 0 lim (\frac{sin ( 2 x )}{arcsin ( x )})

What is the derivative of (6x+7^2) ?
The derivative of (6x+7^2) is 12(6x+7)
What is the first derivative of (6x+7^2) ?
The first derivative of (6x+7^2) is 12(6x+7)