What is the derivative of sqrt(2x+7) ?

The derivative of sqrt(2x+7) is 1/(sqrt(2x+7))

What is the first derivative of sqrt(2x+7) ?

The first derivative of sqrt(2x+7) is 1/(sqrt(2x+7))

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derivative of

2 x + 7

\frac{1}{2 x + 7}

Solution steps

\frac{d}{d x} (2 x + 7)

Apply the chain rule:

\frac{1}{2 2 x + 7} \frac{d}{d x} (2 x + 7)

= \frac{1}{2 2 x + 7} \frac{d}{d x} (2 x + 7)

\frac{d}{d x} (2 x + 7) = 2

= \frac{1}{2 2 x + 7} \cdot 2

Simplify

\frac{1}{2 2 x + 7} \cdot 2 : \frac{1}{2 x + 7}

= \frac{1}{2 x + 7}

(2 x y^{2} - 5) d x + (2 x^{2} y + 4) d y = 0

x \to 1 lim (x^{4} - 1)

g (x) = 3 - x

\frac{\partial}{\partial x} (4 x + 16 y)

7 e^{- x} + e^{3 x}

What is the derivative of sqrt(2x+7) ?
The derivative of sqrt(2x+7) is 1/(sqrt(2x+7))
What is the first derivative of sqrt(2x+7) ?
The first derivative of sqrt(2x+7) is 1/(sqrt(2x+7))