What is the first derivative of 16x^2 ?

The first derivative of 16x^2 is 32x

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derivative of 16x^2

\frac{d}{d x} (16 x^{2})

32 x

Solution steps

\frac{d}{d x} (16 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 16 \cdot 2 x^{2 - 1}

Simplify

= 32 x

\frac{d}{d x} (\frac{3 x ^{2}}{2} - \frac{7}{5 x ^{2}})

\frac{d ^{2}}{d x ^{2}} (\frac{1}{1 - t ^{2}})

y = 3 x^{2} - 4 x + 5

y = ln (x) x

\int_{0}^{2 π} sin (x) + cos (x) d x