What is the first derivative of 0.015+x ?

The first derivative of 0.015+x is 1

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derivative of 0.015+x

\frac{d}{d x} (0.015 + x)

1

Solution steps

\frac{d}{d x} (0.015 + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.015) + \frac{d x}{d x}

\frac{d}{d x} (0.015) = 0

\frac{d x}{d x} = 1

= 0 + 1

Simplify

= 1

f (x) = 6 x^{2} - 10 x + 4, at x = 1

x \to 3 lim (ln (x))

\frac{d ^{2}}{d x ^{2}} (cos^{2} (x))

\int e^{2 y} - y cos (x y) d x

\frac{d}{d x} (4.9 x^{2})