What is the derivative of (4(-x^2-4)/((x^2-4)^2)) ?

The derivative of (4(-x^2-4)/((x^2-4)^2)) is -(8x(-x^2-12))/((x^2-4)^3)

What is the first derivative of (4(-x^2-4)/((x^2-4)^2)) ?

The first derivative of (4(-x^2-4)/((x^2-4)^2)) is -(8x(-x^2-12))/((x^2-4)^3)

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\frac{d}{d x} (\frac{4 ( - x ^{2} - 4 )}{( x ^{2} - 4 ) ^{2}})

- \frac{8 x ( - x ^{2} - 12 )}{( x ^{2} - 4 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{4 ( - x ^{2} - 4 )}{( x ^{2} - 4 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{- x ^{2} - 4}{( x ^{2} - 4 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d}{d x} ( - x ^{2} - 4 ) ( x ^{2} - 4 ) ^{2} - \frac{d}{d x} ( ( x ^{2} - 4 ) ^{2} ) ( - x ^{2} - 4 )}{( ( x ^{2} - 4 ) ^{2} ) ^{2}}

\frac{d}{d x} (- x^{2} - 4) = - 2 x

\frac{d}{d x} ((x^{2} - 4)^{2}) = 4 x (x^{2} - 4)

= 4 \cdot \frac{( - 2 x ) ( x ^{2} - 4 ) ^{2} - 4 x ( x ^{2} - 4 ) ( - x ^{2} - 4 )}{( ( x ^{2} - 4 ) ^{2} ) ^{2}}

Simplify

4 \cdot \frac{( - 2 x ) ( x ^{2} - 4 ) ^{2} - 4 x ( x ^{2} - 4 ) ( - x ^{2} - 4 )}{( ( x ^{2} - 4 ) ^{2} ) ^{2}} : - \frac{8 x ( - x ^{2} - 12 )}{( x ^{2} - 4 ) ^{3}}

= - \frac{8 x ( - x ^{2} - 12 )}{( x ^{2} - 4 ) ^{3}}

(x^{2} sin (x^{2}))^{^{'}}

\int \frac{( 4 x ^{3} - 6 x ^{4} )}{2 x ^{6}} d x

f (x) = 2 x^{4} + 3 x - 3, (2, 35)

9 a^{2} + 8 a - 56

t = 0 \sum \infty \frac{1}{t ^{0.51}}

What is the derivative of (4(-x^2-4)/((x^2-4)^2)) ?
The derivative of (4(-x^2-4)/((x^2-4)^2)) is -(8x(-x^2-12))/((x^2-4)^3)
What is the first derivative of (4(-x^2-4)/((x^2-4)^2)) ?
The first derivative of (4(-x^2-4)/((x^2-4)^2)) is -(8x(-x^2-12))/((x^2-4)^3)