What is the tangent of f(x)= 1/(x^4),\at x=1 ?

The tangent of f(x)= 1/(x^4),\at x=1 is y=-4x+5

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tangent of f(x)= 1/(x^4),\at x=1

tangent of

f (x) = \frac{1}{x ^{4}}, at x = 1

y = - 4 x + 5

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = \frac{1}{x ^{4}} : \frac{df ( x )}{d x} = - \frac{4}{x ^{5}}

Compute the slope of

f (x) = \frac{1}{x ^{4}}

x = 1 : m = - 4

Find the line with slope m=

- 4

and passing through

(1, 1) : y = - 4 x + 5

y = - 4 x + 5

\int \frac{6 x ^{5} + 2 x}{x ^{6} + x ^{2}} d x

\frac{d}{d x} (x^{\frac{4}{9}})

\int_{6}^{8} \frac{32}{( x - 6 ) ^{3}} d x

\frac{2 x}{x - 3}

y^{^{'}} + y = e^{x} y^{2}

What is the tangent of f(x)= 1/(x^4),\at x=1 ?
The tangent of f(x)= 1/(x^4),\at x=1 is y=-4x+5