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Popular >

y^'+y=e^xy^2

Solution

y^{^{'}} + y = e^{x} y^{2}

Solution

y = \frac{1}{e ^{x} ( - x + c _{1} )}

Solution steps

y^{'} (x) + y = e^{x} y^{2}

Solve Bernoulli ODE:

y = \frac{1}{e ^{x} ( - x + c _{1} )}

y = \frac{1}{e ^{x} ( - x + c _{1} )}

Popular Examples

integral from 1 to 2 of ((2x+1)(x-2))/x

\int_{1}^{2} \frac{( 2 x + 1 ) ( x - 2 )}{x} d x

derivative of f(x)= x/(x-7)derivative of

f (x) = \frac{x}{x - 7}

y^{''}+3y^'+2y= 1/(7+e^x)

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{7 + e ^{x}}

derivative of 1+1/(2x)

\frac{d}{d x} (1 + \frac{1}{2 x})

derivative of y=(sqrt(x)-5)/(sqrt(x)+5)derivative of

y = \frac{x - 5}{x + 5}

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=e^xy^2 ?
The solution for y^'+y=e^xy^2 is y= 1/(e^x(-x+c_{1))}