What is (\partial)/(\partial y)(ycos(z)) ?

The answer to (\partial)/(\partial y)(ycos(z)) is cos(z)

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(\partial)/(\partial y)(ycos(z))

\frac{\partial}{\partial y} (y cos (z))

cos (z)

Solution steps

\frac{\partial}{\partial y} (y cos (z))

Treat

z

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (z) \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= cos (z) \cdot 1

Simplify

= cos (z)

\int e^{3 x} cos (3 x) d x

\frac{\partial}{\partial y} (z^{2})

x \to \frac{π}{5} lim (cot (5 x))

\frac{\partial}{\partial x} (x y - x + y)

\int \frac{x ^{2} - 16}{x ^{2}} d x

What is (\partial)/(\partial y)(ycos(z)) ?
The answer to (\partial)/(\partial y)(ycos(z)) is cos(z)