What is (\partial)/(\partial x)(xy-x+y) ?

The answer to (\partial)/(\partial x)(xy-x+y) is y-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(xy-x+y)

\frac{\partial}{\partial x} (x y - x + y)

y - 1

Solution steps

\frac{\partial}{\partial x} (x y - x + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= y - 1 + 0

Simplify

= y - 1

\int \frac{x ^{2} - 16}{x ^{2}} d x

0, x^{2}, - x + 5

\int \frac{1}{cos ( x - 1 )} d x

f (x) = x^{3} - 2 x

x \to 2 lim ([6 f (x) + g (x)])

What is (\partial)/(\partial x)(xy-x+y) ?
The answer to (\partial)/(\partial x)(xy-x+y) is y-1