What is the derivative of f(x)=x^3-2x ?

The derivative of f(x)=x^3-2x is 3x^2-2

What is the first derivative of f(x)=x^3-2x ?

The first derivative of f(x)=x^3-2x is 3x^2-2

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derivative of

f (x) = x^{3} - 2 x

3 x^{2} - 2

Solution steps

\frac{d}{d x} (x^{3} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x) = 2

= 3 x^{2} - 2

x \to 2 lim ([6 f (x) + g (x)])

4 x + 10, x^{2} + 6 x + 6, - 2, 2

(x^{2} + 16) \frac{d y}{d x} + x y = 5 x

lo g_{8} (5 x^{3} + 3 x)

\frac{8 x ^{2} + 8 x + 8}{x}

What is the derivative of f(x)=x^3-2x ?
The derivative of f(x)=x^3-2x is 3x^2-2
What is the first derivative of f(x)=x^3-2x ?
The first derivative of f(x)=x^3-2x is 3x^2-2