What is area 4x+10,x^2+6x+6,-2,2 ?

The answer to area 4x+10,x^2+6x+6,-2,2 is (32-16sqrt(5))/3+12sqrt(5)-12

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area 4x+10,x^2+6x+6,-2,2

area

4 x + 10, x^{2} + 6 x + 6, - 2, 2

\frac{32 - 16 5}{3} + 125 - 12

Decimal Notation

13.57378 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} 4 x + 10 - (x^{2} + 6 x + 6) d x

Solve

\int_{- 2}^{2} 4 x + 10 - (x^{2} + 6 x + 6) d x : \frac{32 - 16 5}{3} + 125 - 12

The area is:

= \frac{32 - 16 5}{3} + 125 - 12

(x^{2} + 16) \frac{d y}{d x} + x y = 5 x

lo g_{8} (5 x^{3} + 3 x)

\frac{8 x ^{2} + 8 x + 8}{x}

x \frac{9}{6}, 7

\int_{0}^{2} (1 + x^{2}) d x

What is area 4x+10,x^2+6x+6,-2,2 ?
The answer to area 4x+10,x^2+6x+6,-2,2 is (32-16sqrt(5))/3+12sqrt(5)-12