What is taylor x 9/6 ,7 ?

The answer to taylor x 9/6 ,7 is 21/2+3/2 (x-7)

Popular >

taylor x 9/6 ,7

taylor

x \frac{9}{6}, 7

\frac{21}{2} + \frac{3}{2} (x - 7)

Solution steps

Apply the Taylor Formula

= \frac{21}{2} + \frac{\frac{d}{d x} ( x \frac{9}{6} ) ( 7 )}{1 !} (x - 7) + \frac{\frac{d ^{2}}{d x ^{2}} ( x \frac{9}{6} ) ( 7 )}{2 !} (x - 7)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x \frac{9}{6} ) ( 7 )}{3 !} (x - 7)^{3} + \dots

Evaluate Derivatives

= \frac{21}{2} + \frac{\frac{3}{2}}{1 !} (x - 7) + \frac{0}{2 !} (x - 7)^{2} + \frac{0}{3 !} (x - 7)^{3} + \frac{0}{4 !} (x - 7)^{4} + \frac{0}{5 !} (x - 7)^{5} + \frac{0}{6 !} (x - 7)^{6} + \frac{0}{7 !} (x - 7)^{7} + \frac{0}{8 !} (x - 7)^{8} + \frac{0}{9 !} (x - 7)^{9} + \frac{0}{10 !} (x - 7)^{10}

Refine

= \frac{21}{2} + \frac{3}{2} (x - 7)

\int_{0}^{2} (1 + x^{2}) d x

\frac{\partial}{\partial x} (\frac{x ^{2}}{16 - y ^{2}})

y^{'}, x^{2} - y^{2} = 9

\frac{d}{d x} (3 cos (2 x) + sin (2 x) + 4)

(5, \frac{1}{2}), (\frac{495}{62}, 3)