What is implicit y',x^2-y^2=9 ?

The answer to implicit y',x^2-y^2=9 is y'= x/y

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implicit y',x^2-y^2=9

implicit derivative

y^{'} (x), x^{2} - y^{2} = 9

y' = \frac{x}{y}

Solution steps

x^{2} - y^{2} = 9

Treat

y

y (x)

Differentiate both sides:

2 x - 2 y f_{1}^{'} (x) = 0

Isolate

\frac{d y}{d x} : y^{'} = \frac{x}{y}

y^{^{'}} = \frac{x}{y}

\frac{d}{d x} (3 cos (2 x) + sin (2 x) + 4)

(5, \frac{1}{2}), (\frac{495}{62}, 3)

\int \frac{1}{tan ( 5 x )} d x

\int (x^{2} - 10 x + 24) ln (x) d x

f (x) = \frac{1}{2 + 3 x}, (1, \frac{1}{5})