What is the integral of 1/(tan(5x)) ?

The integral of 1/(tan(5x)) is 1/5 ln|sin(5x)|+C

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integral of 1/(tan(5x))

\int \frac{1}{tan ( 5 x )} d x

\frac{1}{5} ln ∣ sin (5 x) ∣ + C

Solution steps

\int \frac{1}{tan ( 5 x )} d x

Rewrite using trig identities

= \int \frac{cos ( 5 x )}{sin ( 5 x )} d x

Apply u-substitution

: \int \frac{1}{5 u} d u

= \int \frac{1}{5 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{5} ln ∣ u ∣

Substitute back

u = sin (5 x)

= \frac{1}{5} ln ∣ sin (5 x) ∣

Add a constant to the solution

= \frac{1}{5} ln ∣ sin (5 x) ∣ + C

\int (x^{2} - 10 x + 24) ln (x) d x

f (x) = \frac{1}{2 + 3 x}, (1, \frac{1}{5})

e^{- 2 t} t

e^{x}, - 4

\frac{\partial}{\partial y} ((2 x + 3 y)^{10})

What is the integral of 1/(tan(5x)) ?
The integral of 1/(tan(5x)) is 1/5 ln|sin(5x)|+C