What is the integral from 0 to 0.07 of 600x ?

The integral from 0 to 0.07 of 600x is 1.47

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 0.07 of 600x

\int_{0}^{0.07} 600 x d x

1.47

Solution steps

\int_{0}^{0.07} 600 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 600 \cdot \int_{0}^{0.07} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.07}

= 600 [\frac{x ^{2}}{2}]_{0}^{0.07}

Simplify

= 600 [0.5 x^{2}]_{0}^{0.07}

Compute the boundaries:

0.00245

= 600 \cdot 0.00245

Simplify

= 1.47

\int_{0}^{\frac{π}{6}} tan (2 x) d x

y + x^{2} + y^{2} - x y^{^{'}} = 0

f (x) = 2 e^{x} cos (x)

e^{8 e^{x}}

\int_{5}^{\infty} x e^{- 3 x} d x

What is the integral from 0 to 0.07 of 600x ?
The integral from 0 to 0.07 of 600x is 1.47