What is the solution for y+sqrt(x^2+y^2)-xy^'=0 ?

The solution for y+sqrt(x^2+y^2)-xy^'=0 is y=-1/(2e^{c_{1)}}+(e^{c_{1}}x^2)/2

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y+sqrt(x^2+y^2)-xy^'=0

y + x^{2} + y^{2} - x y^{^{'}} = 0

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

Solution steps

y + x^{2} + y^{2} - x y^{'} (x) = 0

Solve using substitution:

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

f (x) = 2 e^{x} cos (x)

e^{8 e^{x}}

\int_{5}^{\infty} x e^{- 3 x} d x

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\int e^{20 t} 6 sin (2 t) d t

What is the solution for y+sqrt(x^2+y^2)-xy^'=0 ?
The solution for y+sqrt(x^2+y^2)-xy^'=0 is y=-1/(2e^{c_{1)}}+(e^{c_{1}}x^2)/2