What is the integral of ((1+x)^3)/(sqrt(x)) ?

The integral of ((1+x)^3)/(sqrt(x)) is 2sqrt(x)+2x^{3/2}+6/5 x^{5/2}+2/7 x^{7/2}+C

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integral of ((1+x)^3)/(sqrt(x))

\int \frac{( 1 + x ) ^{3}}{x} d x

2 x + 2 x^{\frac{3}{2}} + \frac{6}{5} x^{\frac{5}{2}} + \frac{2}{7} x^{\frac{7}{2}} + C

Solution steps

\int \frac{( 1 + x ) ^{3}}{x} d x

Expand

\frac{( 1 + x ) ^{3}}{x} : \frac{1}{x} + 3 x + 3 x^{\frac{3}{2}} + x^{\frac{5}{2}}

= \int \frac{1}{x} + 3 x + 3 x^{\frac{3}{2}} + x^{\frac{5}{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x + \int 3 x d x + \int 3 x^{\frac{3}{2}} d x + \int x^{\frac{5}{2}} d x

\int \frac{1}{x} d x = 2 x

\int 3 x d x = 2 x^{\frac{3}{2}}

\int 3 x^{\frac{3}{2}} d x = \frac{6}{5} x^{\frac{5}{2}}

\int x^{\frac{5}{2}} d x = \frac{2}{7} x^{\frac{7}{2}}

= 2 x + 2 x^{\frac{3}{2}} + \frac{6}{5} x^{\frac{5}{2}} + \frac{2}{7} x^{\frac{7}{2}}

Add a constant to the solution

= 2 x + 2 x^{\frac{3}{2}} + \frac{6}{5} x^{\frac{5}{2}} + \frac{2}{7} x^{\frac{7}{2}} + C

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\frac{d}{d x} ((2 x - 1)^{3} (3 x + 2)^{4})

\frac{d y}{d x} = tan (x)

n = 0 \sum \infty x^{(1 + n)}

\int_{- 1}^{0} - 5 x (3 x^{2} - 2)^{3} d x

What is the integral of ((1+x)^3)/(sqrt(x)) ?
The integral of ((1+x)^3)/(sqrt(x)) is 2sqrt(x)+2x^{3/2}+6/5 x^{5/2}+2/7 x^{7/2}+C