What is the sum from n=5 to infinity of 4-4/(n^2) ?

The sum from n=5 to infinity of 4-4/(n^2) is diverges

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sum from n=5 to infinity of 4-4/(n^2)

n = 5 \sum \infty 4 - \frac{4}{n ^{2}}

diverges

Solution steps

n = 5 \sum \infty 4 - \frac{4}{n ^{2}}

Apply Series Divergence Test:

diverges

= diverges

y^{^{'}} = \frac{2 t}{3 y ^{2}}

y^{^{'}} = 14 x y

\frac{d}{d x} (7 + 6 x)

\int \frac{( 3 x ^{4} )}{x ^{2} - 2 x} d x

f (x) = 3 x^{4}, at x = - 1

What is the sum from n=5 to infinity of 4-4/(n^2) ?
The sum from n=5 to infinity of 4-4/(n^2) is diverges